3x-4(x+1)+12=0

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Solution for 3x-4(x+1)+12=0 equation:


Simplifying
3x + -4(x + 1) + 12 = 0

Reorder the terms:
3x + -4(1 + x) + 12 = 0
3x + (1 * -4 + x * -4) + 12 = 0
3x + (-4 + -4x) + 12 = 0

Reorder the terms:
-4 + 12 + 3x + -4x = 0

Combine like terms: -4 + 12 = 8
8 + 3x + -4x = 0

Combine like terms: 3x + -4x = -1x
8 + -1x = 0

Solving
8 + -1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1x = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1x = 0 + -8
-1x = 0 + -8

Combine like terms: 0 + -8 = -8
-1x = -8

Divide each side by '-1'.
x = 8

Simplifying
x = 8

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