3x-4(x+1)=1-6x

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Solution for 3x-4(x+1)=1-6x equation: 



3x-4(x+1)=1-6x

We move all terms to the left:

3x-4(x+1)-(1-6x)=0

We add all the numbers together, and all the variables

3x-4(x+1)-(-6x+1)=0

We multiply parentheses

3x-4x-(-6x+1)-4=0

We get rid of parentheses

3x-4x+6x-1-4=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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