3x-4(x+2)=13

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Solution for 3x-4(x+2)=13 equation: 



3x-4(x+2)=13

We move all terms to the left:

3x-4(x+2)-(13)=0

We multiply parentheses

3x-4x-8-13=0

We add all the numbers together, and all the variables

-1x-21=0

We move all terms containing x to the left, all other terms to the right

-x=21

x=21/-1

x=-21

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