3x-4(x+2)=2(-x-1)

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Solution for 3x-4(x+2)=2(-x-1) equation: 



3x-4(x+2)=2(-x-1)

We move all terms to the left:

3x-4(x+2)-(2(-x-1))=0

We add all the numbers together, and all the variables

3x-4(x+2)-(2(-1x-1))=0

We multiply parentheses

3x-4x-(2(-1x-1))-8=0



We calculate terms in parentheses: -(2(-1x-1)), so:

2(-1x-1)

We multiply parentheses

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

-1x-(-2x-2)-8=0

We get rid of parentheses

-1x+2x+2-8=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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