3x-4(x+3)=21

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Solution for 3x-4(x+3)=21 equation: 



3x-4(x+3)=21

We move all terms to the left:

3x-4(x+3)-(21)=0

We multiply parentheses

3x-4x-12-21=0

We add all the numbers together, and all the variables

-1x-33=0

We move all terms containing x to the left, all other terms to the right

-x=33

x=33/-1

x=-33

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