3x-4(x+4)=x+3-(9-6x)

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Solution for 3x-4(x+4)=x+3-(9-6x) equation: 



3x-4(x+4)=x+3-(9-6x)

We move all terms to the left:

3x-4(x+4)-(x+3-(9-6x))=0

We add all the numbers together, and all the variables

3x-4(x+4)-(x+3-(-6x+9))=0

We multiply parentheses

3x-4x-(x+3-(-6x+9))-16=0



We calculate terms in parentheses: -(x+3-(-6x+9)), so:

x+3-(-6x+9)

determiningTheFunctionDomain
x-(-6x+9)+3

We get rid of parentheses

x+6x-9+3

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

-1x-(7x-6)-16=0

We get rid of parentheses

-1x-7x+6-16=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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