3x-4(x+5)=7+3(2-3x)

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Solution for 3x-4(x+5)=7+3(2-3x) equation: 



3x-4(x+5)=7+3(2-3x)

We move all terms to the left:

3x-4(x+5)-(7+3(2-3x))=0

We add all the numbers together, and all the variables

3x-4(x+5)-(7+3(-3x+2))=0

We multiply parentheses

3x-4x-(7+3(-3x+2))-20=0



We calculate terms in parentheses: -(7+3(-3x+2)), so:

7+3(-3x+2)

determiningTheFunctionDomain
3(-3x+2)+7

We multiply parentheses

-9x+6+7

We add all the numbers together, and all the variables

-9x+13

Back to the equation:

-(-9x+13)



We add all the numbers together, and all the variables

-1x-(-9x+13)-20=0

We get rid of parentheses

-1x+9x-13-20=0

We add all the numbers together, and all the variables

8x-33=0

We move all terms containing x to the left, all other terms to the right

8x=33

x=33/8

x=4+1/8

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