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3x-4(x-2)=(5+4x)
We move all terms to the left:
3x-4(x-2)-((5+4x))=0
We add all the numbers together, and all the variables
3x-4(x-2)-((4x+5))=0
We multiply parentheses
3x-4x-((4x+5))+8=0
We calculate terms in parentheses: -((4x+5)), so:We add all the numbers together, and all the variables
(4x+5)
We get rid of parentheses
4x+5
Back to the equation:
-(4x+5)
-1x-(4x+5)+8=0
We get rid of parentheses
-1x-4x-5+8=0
We add all the numbers together, and all the variables
-5x+3=0
We move all terms containing x to the left, all other terms to the right
-5x=-3
x=-3/-5
x=3/5
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