3x-4(x-2)=5-3(x+2)

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Solution for 3x-4(x-2)=5-3(x+2) equation: 



3x-4(x-2)=5-3(x+2)

We move all terms to the left:

3x-4(x-2)-(5-3(x+2))=0

We multiply parentheses

3x-4x-(5-3(x+2))+8=0



We calculate terms in parentheses: -(5-3(x+2)), so:

5-3(x+2)

determiningTheFunctionDomain
-3(x+2)+5

We multiply parentheses

-3x-6+5

We add all the numbers together, and all the variables

-3x-1

Back to the equation:

-(-3x-1)



We add all the numbers together, and all the variables

-1x-(-3x-1)+8=0

We get rid of parentheses

-1x+3x+1+8=0

We add all the numbers together, and all the variables

2x+9=0

We move all terms containing x to the left, all other terms to the right

2x=-9

x=-9/2

x=-4+1/2

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