3x-4(x-2)=5-3(x+2)

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Solution for 3x-4(x-2)=5-3(x+2) equation:



3x-4(x-2)=5-3(x+2)
We move all terms to the left:
3x-4(x-2)-(5-3(x+2))=0
We multiply parentheses
3x-4x-(5-3(x+2))+8=0
We calculate terms in parentheses: -(5-3(x+2)), so:
5-3(x+2)
determiningTheFunctionDomain -3(x+2)+5
We multiply parentheses
-3x-6+5
We add all the numbers together, and all the variables
-3x-1
Back to the equation:
-(-3x-1)
We add all the numbers together, and all the variables
-1x-(-3x-1)+8=0
We get rid of parentheses
-1x+3x+1+8=0
We add all the numbers together, and all the variables
2x+9=0
We move all terms containing x to the left, all other terms to the right
2x=-9
x=-9/2
x=-4+1/2

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