3x-4(x-3)+10=5(2x-4)-(x+5)

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Solution for 3x-4(x-3)+10=5(2x-4)-(x+5) equation: 



3x-4(x-3)+10=5(2x-4)-(x+5)

We move all terms to the left:

3x-4(x-3)+10-(5(2x-4)-(x+5))=0

We multiply parentheses

3x-4x-(5(2x-4)-(x+5))+12+10=0



We calculate terms in parentheses: -(5(2x-4)-(x+5)), so:

5(2x-4)-(x+5)

We multiply parentheses

10x-(x+5)-20

We get rid of parentheses

10x-x-5-20

We add all the numbers together, and all the variables

9x-25

Back to the equation:

-(9x-25)



We add all the numbers together, and all the variables

-1x-(9x-25)+22=0

We get rid of parentheses

-1x-9x+25+22=0

We add all the numbers together, and all the variables

-10x+47=0

We move all terms containing x to the left, all other terms to the right

-10x=-47

x=-47/-10

x=4+7/10

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