3x-4+0,2x=15+1,2+21

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Solution for 3x-4+0,2x=15+1,2+21 equation: 



3x-4+0.2x=15+1.2+21

We move all terms to the left:

3x-4+0.2x-(15+1.2+21)=0

We add all the numbers together, and all the variables

3x+0.2x-4-(37.2)=0

We add all the numbers together, and all the variables

3.2x-41.2=0

We move all terms containing x to the left, all other terms to the right

3.2x=41.2

x=41.2/3.2

x=12+2.8/3.2

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