3x-4-(5x-8)=-(x+12)-6x+1

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Solution for 3x-4-(5x-8)=-(x+12)-6x+1 equation: 



3x-4-(5x-8)=-(x+12)-6x+1

We move all terms to the left:

3x-4-(5x-8)-(-(x+12)-6x+1)=0

We get rid of parentheses

3x-5x-(-(x+12)-6x+1)+8-4=0



We calculate terms in parentheses: -(-(x+12)-6x+1), so:

-(x+12)-6x+1

We add all the numbers together, and all the variables

-6x-(x+12)+1

We get rid of parentheses

-6x-x-12+1

We add all the numbers together, and all the variables

-7x-11

Back to the equation:

-(-7x-11)



We add all the numbers together, and all the variables

-2x-(-7x-11)+4=0

We get rid of parentheses

-2x+7x+11+4=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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