3x-4-1x=-4x-(-3+x)

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Solution for 3x-4-1x=-4x-(-3+x) equation: 



3x-4-1x=-4x-(-3+x)

We move all terms to the left:

3x-4-1x-(-4x-(-3+x))=0

We add all the numbers together, and all the variables

3x-1x-(-4x-(x-3))-4=0

We add all the numbers together, and all the variables

2x-(-4x-(x-3))-4=0



We calculate terms in parentheses: -(-4x-(x-3)), so:

-4x-(x-3)

We get rid of parentheses

-4x-x+3

We add all the numbers together, and all the variables

-5x+3

Back to the equation:

-(-5x+3)



We get rid of parentheses

2x+5x-3-4=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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