3x-4-4(x+1)=0

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Solution for 3x-4-4(x+1)=0 equation: 



3x-4-4(x+1)=0

We multiply parentheses

3x-4x-4-4=0

We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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