3x-4-4(x+1)=0

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Solution for 3x-4-4(x+1)=0 equation:



3x-4-4(x+1)=0
We multiply parentheses
3x-4x-4-4=0
We add all the numbers together, and all the variables
-1x-8=0
We move all terms containing x to the left, all other terms to the right
-x=8
x=8/-1
x=-8

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