3x-4/1-2x=x-8/x+7

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Solution for 3x-4/1-2x=x-8/x+7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-(2*x)-(4/1) = x-(8/x)+7 // - x-(8/x)+7

3*x-(2*x)-x+8/x-(4/1)-7 = 0

3*x-2*x-x+8/x-7-4 = 0

8*x^-1 = 11 // : 8

x^-1 = 11/8

-1 < 0

1/(x^1) = 11/8 // * x^1

1 = 11/8*x^1 // : 11/8

8/11 = x^1

x = 8/11

x = 8/11

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