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3x-4/2+5=2(x-3)
We move all terms to the left:
3x-4/2+5-(2(x-3))=0
We add all the numbers together, and all the variables
3x-(2(x-3))+3=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
3x-2x+6+3=0
We add all the numbers together, and all the variables
x+9=0
We move all terms containing x to the left, all other terms to the right
x=-9
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