3x-4/4-x+1/5=2x+7/10

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Solution for 3x-4/4-x+1/5=2x+7/10 equation: 


x in (-oo:+oo)

3*x-x-(4/4)+1/5 = 2*x+7/10 // - 2*x+7/10

3*x-x-(2*x)-(4/4)+1/5-(7/10) = 0

3*x-x-2*x+1/5-7/10-1 = 0

-3/2 = 0

x belongs to the empty set

x belongs to the empty set

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