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3x-4/x+1=2x+9/4x
We move all terms to the left:
3x-4/x+1-(2x+9/4x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-4/x-(+2x+9/4x)+1=0
We get rid of parentheses
3x-4/x-2x-9/4x+1=0
We calculate fractions
3x-2x+(-16x)/4x^2+(-9x)/4x^2+1=0
We add all the numbers together, and all the variables
x+(-16x)/4x^2+(-9x)/4x^2+1=0
We multiply all the terms by the denominator
x*4x^2+(-16x)+(-9x)+1*4x^2=0
Wy multiply elements
4x^3+4x^2+(-16x)+(-9x)=0
We get rid of parentheses
4x^3+4x^2-16x-9x=0
We do not support expression: x^3
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