3x-41/2=1912

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Solution for 3x-41/2=1912 equation: 



3x-41/2=1912

We move all terms to the left:

3x-41/2-(1912)=0

determiningTheFunctionDomain
3x-1912-41/2=0

We multiply all the terms by the denominator


3x*2-41-1912*2=0

We add all the numbers together, and all the variables

3x*2-3865=0

Wy multiply elements

6x-3865=0

We move all terms containing x to the left, all other terms to the right

6x=3865

x=3865/6

x=644+1/6

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