3x-42=3(3x-2)

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Solution for 3x-42=3(3x-2) equation: 



3x-42=3(3x-2)

We move all terms to the left:

3x-42-(3(3x-2))=0



We calculate terms in parentheses: -(3(3x-2)), so:

3(3x-2)

We multiply parentheses

9x-6

Back to the equation:

-(9x-6)



We get rid of parentheses

3x-9x+6-42=0

We add all the numbers together, and all the variables

-6x-36=0

We move all terms containing x to the left, all other terms to the right

-6x=36

x=36/-6

x=-6

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