3x-42=3(3x-2)

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Solution for 3x-42=3(3x-2) equation:



3x-42=3(3x-2)
We move all terms to the left:
3x-42-(3(3x-2))=0
We calculate terms in parentheses: -(3(3x-2)), so:
3(3x-2)
We multiply parentheses
9x-6
Back to the equation:
-(9x-6)
We get rid of parentheses
3x-9x+6-42=0
We add all the numbers together, and all the variables
-6x-36=0
We move all terms containing x to the left, all other terms to the right
-6x=36
x=36/-6
x=-6

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