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3x-472=4/x
We move all terms to the left:
3x-472-(4/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+4/x)-472=0
We get rid of parentheses
3x-4/x-472=0
We multiply all the terms by the denominator
3x*x-472*x-4=0
We add all the numbers together, and all the variables
-472x+3x*x-4=0
Wy multiply elements
3x^2-472x-4=0
a = 3; b = -472; c = -4;
Δ = b2-4ac
Δ = -4722-4·3·(-4)
Δ = 222832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{222832}=\sqrt{16*13927}=\sqrt{16}*\sqrt{13927}=4\sqrt{13927}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-472)-4\sqrt{13927}}{2*3}=\frac{472-4\sqrt{13927}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-472)+4\sqrt{13927}}{2*3}=\frac{472+4\sqrt{13927}}{6} $
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