3x-4=(1/2)5x+20

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Solution for 3x-4=(1/2)5x+20 equation: 



3x-4=(1/2)5x+20

We move all terms to the left:

3x-4-((1/2)5x+20)=0



Domain of the equation: 2)5x+20)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x-((+1/2)5x+20)-4=0

We multiply all the terms by the denominator


3x*2)5x+20)-((-4*2)5x+20)+1=0

We add all the numbers together, and all the variables

3x*2)5x+20)-((-8)5x+20)+1=0

Wy multiply elements

6x^2-8)5x+20)+1=0

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