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3x-4=2(2-3x)-7x
We move all terms to the left:
3x-4-(2(2-3x)-7x)=0
We add all the numbers together, and all the variables
3x-(2(-3x+2)-7x)-4=0
We calculate terms in parentheses: -(2(-3x+2)-7x), so:We get rid of parentheses
2(-3x+2)-7x
We add all the numbers together, and all the variables
-7x+2(-3x+2)
We multiply parentheses
-7x-6x+4
We add all the numbers together, and all the variables
-13x+4
Back to the equation:
-(-13x+4)
3x+13x-4-4=0
We add all the numbers together, and all the variables
16x-8=0
We move all terms containing x to the left, all other terms to the right
16x=8
x=8/16
x=1/2
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