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3x-4=2/x-1
We move all terms to the left:
3x-4-(2/x-1)=0
Domain of the equation: x-1)!=0We get rid of parentheses
x∈R
3x-2/x+1-4=0
We multiply all the terms by the denominator
3x*x+1*x-4*x-2=0
We add all the numbers together, and all the variables
-3x+3x*x-2=0
Wy multiply elements
3x^2-3x-2=0
a = 3; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·3·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{33}}{2*3}=\frac{3-\sqrt{33}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{33}}{2*3}=\frac{3+\sqrt{33}}{6} $
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