3x-4=3(2x-2)-7

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Solution for 3x-4=3(2x-2)-7 equation: 



3x-4=3(2x-2)-7

We move all terms to the left:

3x-4-(3(2x-2)-7)=0



We calculate terms in parentheses: -(3(2x-2)-7), so:

3(2x-2)-7

We multiply parentheses

6x-6-7

We add all the numbers together, and all the variables

6x-13

Back to the equation:

-(6x-13)



We get rid of parentheses

3x-6x+13-4=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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