3x-4=3(x-1)+12

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Solution for 3x-4=3(x-1)+12 equation: 



3x-4=3(x-1)+12

We move all terms to the left:

3x-4-(3(x-1)+12)=0



We calculate terms in parentheses: -(3(x-1)+12), so:

3(x-1)+12

We multiply parentheses

3x-3+12

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

3x-3x-9-4=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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