3x-4=3(x-4)+12

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Solution for 3x-4=3(x-4)+12 equation: 


Simplifying
3x + -4 = 3(x + -4) + 12

Reorder the terms:
-4 + 3x = 3(x + -4) + 12

Reorder the terms:
-4 + 3x = 3(-4 + x) + 12
-4 + 3x = (-4 * 3 + x * 3) + 12
-4 + 3x = (-12 + 3x) + 12

Reorder the terms:
-4 + 3x = -12 + 12 + 3x

Combine like terms: -12 + 12 = 0
-4 + 3x = 0 + 3x
-4 + 3x = 3x

Add '-3x' to each side of the equation.
-4 + 3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
-4 + 0 = 3x + -3x
-4 = 3x + -3x

Combine like terms: 3x + -3x = 0
-4 = 0

Solving
-4 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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