3x-4=8-2(x+1)

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Solution for 3x-4=8-2(x+1) equation: 



3x-4=8-2(x+1)

We move all terms to the left:

3x-4-(8-2(x+1))=0



We calculate terms in parentheses: -(8-2(x+1)), so:

8-2(x+1)

determiningTheFunctionDomain
-2(x+1)+8

We multiply parentheses

-2x-2+8

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

3x+2x-6-4=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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