3x-4=x(1/2)+6

Solution for 3x-4=x(1/2)+6 equation:

3x-4=x(1/2)+6

We move all terms to the left:

3x-4-(x(1/2)+6)=0

We add all the numbers together, and all the variables

3x-(x(+1/2)+6)-4=0

We multiply all the terms by the denominator


3x*2)+6)-(x(+1-4*2)+6)=0

We add all the numbers together, and all the variables

3x*2)+6)-(x(-7)+6)=0

We add all the numbers together, and all the variables

3x*2)+6)-(x(=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$