3x-4y=3;y=x-2

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for example:
2x+y=8
x+3y=14

Solution for 3x-4y=3;y=x-2 system of equations: 


  • /| 3*x-(4*y)-3 = 0| y-x+2 = 0
  • We try to solve the equation: 3*x-(4*y)-3 = 0
  • 3*x-4*y-3 = 0 // - 3*x-3
  • -4*y = -(3*x-3) // : -4
  • y = (-(3*x-3))/(-4)
  • y = (3-(3*x))/(-4)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (3-(3*x))/(-4)-x+2 = 0| y = (3-(3*x))/(-4)
  • (3-3*x)/(-4)-x+2 = 0
  • 2-1/4*x-3/4 = 0
  • 5/4-1/4*x = 0
  • 5/4-1/4*x = 0 // - 5/4
  • -1/4*x = -5/4 // : -1/4
  • x = -5/4/(-1/4)
  • x = 5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (3-(3*x))/(-4): 
  • y = (3-(3*5))/(-4)
  • y = (3-15)/(-4)
  • y = -12/(-4)
  • y = 3
  • We get a system of equations:
  • /| y = 3| x = 5

 

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