3x-5(1-6x)=127

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Solution for 3x-5(1-6x)=127 equation: 



3x-5(1-6x)=127

We move all terms to the left:

3x-5(1-6x)-(127)=0

We add all the numbers together, and all the variables

3x-5(-6x+1)-127=0

We multiply parentheses

3x+30x-5-127=0

We add all the numbers together, and all the variables

33x-132=0

We move all terms containing x to the left, all other terms to the right

33x=132

x=132/33

x=4

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