3x-5(1-x)=9-2(x+3)

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Solution for 3x-5(1-x)=9-2(x+3) equation: 



3x-5(1-x)=9-2(x+3)

We move all terms to the left:

3x-5(1-x)-(9-2(x+3))=0

We add all the numbers together, and all the variables

3x-5(-1x+1)-(9-2(x+3))=0

We multiply parentheses

3x+5x-(9-2(x+3))-5=0



We calculate terms in parentheses: -(9-2(x+3)), so:

9-2(x+3)

determiningTheFunctionDomain
-2(x+3)+9

We multiply parentheses

-2x-6+9

We add all the numbers together, and all the variables

-2x+3

Back to the equation:

-(-2x+3)



We add all the numbers together, and all the variables

8x-(-2x+3)-5=0

We get rid of parentheses

8x+2x-3-5=0

We add all the numbers together, and all the variables

10x-8=0

We move all terms containing x to the left, all other terms to the right

10x=8

x=8/10

x=4/5

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