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3x-5(2x+3)=-6(x-1)
We move all terms to the left:
3x-5(2x+3)-(-6(x-1))=0
We multiply parentheses
3x-10x-(-6(x-1))-15=0
We calculate terms in parentheses: -(-6(x-1)), so:We add all the numbers together, and all the variables
-6(x-1)
We multiply parentheses
-6x+6
Back to the equation:
-(-6x+6)
-7x-(-6x+6)-15=0
We get rid of parentheses
-7x+6x-6-15=0
We add all the numbers together, and all the variables
-1x-21=0
We move all terms containing x to the left, all other terms to the right
-x=21
x=21/-1
x=-21
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