3x-5(x+10)=2(x-2)-(x+40)

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Solution for 3x-5(x+10)=2(x-2)-(x+40) equation: 



3x-5(x+10)=2(x-2)-(x+40)

We move all terms to the left:

3x-5(x+10)-(2(x-2)-(x+40))=0

We multiply parentheses

3x-5x-(2(x-2)-(x+40))-50=0



We calculate terms in parentheses: -(2(x-2)-(x+40)), so:

2(x-2)-(x+40)

We multiply parentheses

2x-(x+40)-4

We get rid of parentheses

2x-x-40-4

We add all the numbers together, and all the variables

x-44

Back to the equation:

-(x-44)



We add all the numbers together, and all the variables

-2x-(x-44)-50=0

We get rid of parentheses

-2x-x+44-50=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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