3x-5(x+2)+22=3(x-2)+13x

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Solution for 3x-5(x+2)+22=3(x-2)+13x equation: 



3x-5(x+2)+22=3(x-2)+13x

We move all terms to the left:

3x-5(x+2)+22-(3(x-2)+13x)=0

We multiply parentheses

3x-5x-(3(x-2)+13x)-10+22=0



We calculate terms in parentheses: -(3(x-2)+13x), so:

3(x-2)+13x

We add all the numbers together, and all the variables

13x+3(x-2)

We multiply parentheses

13x+3x-6

We add all the numbers together, and all the variables

16x-6

Back to the equation:

-(16x-6)



We add all the numbers together, and all the variables

-2x-(16x-6)+12=0

We get rid of parentheses

-2x-16x+6+12=0

We add all the numbers together, and all the variables

-18x+18=0

We move all terms containing x to the left, all other terms to the right

-18x=-18

x=-18/-18

x=1

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