3x-5(x+2)=7-(6-2x)

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Solution for 3x-5(x+2)=7-(6-2x) equation: 



3x-5(x+2)=7-(6-2x)

We move all terms to the left:

3x-5(x+2)-(7-(6-2x))=0

We add all the numbers together, and all the variables

3x-5(x+2)-(7-(-2x+6))=0

We multiply parentheses

3x-5x-(7-(-2x+6))-10=0



We calculate terms in parentheses: -(7-(-2x+6)), so:

7-(-2x+6)

determiningTheFunctionDomain
-(-2x+6)+7

We get rid of parentheses

2x-6+7

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

-2x-(2x+1)-10=0

We get rid of parentheses

-2x-2x-1-10=0

We add all the numbers together, and all the variables

-4x-11=0

We move all terms containing x to the left, all other terms to the right

-4x=11

x=11/-4

x=-2+3/4

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