3x-5(x+3)-18=14+12x-10

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Solution for 3x-5(x+3)-18=14+12x-10 equation: 



3x-5(x+3)-18=14+12x-10

We move all terms to the left:

3x-5(x+3)-18-(14+12x-10)=0

We add all the numbers together, and all the variables

3x-5(x+3)-(12x+4)-18=0

We multiply parentheses

3x-5x-(12x+4)-15-18=0

We get rid of parentheses

3x-5x-12x-4-15-18=0

We add all the numbers together, and all the variables

-14x-37=0

We move all terms containing x to the left, all other terms to the right

-14x=37

x=37/-14

x=-2+9/14

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