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3x-5(x-2)=-7(3x+6)-2
We move all terms to the left:
3x-5(x-2)-(-7(3x+6)-2)=0
We multiply parentheses
3x-5x-(-7(3x+6)-2)+10=0
We calculate terms in parentheses: -(-7(3x+6)-2), so:We add all the numbers together, and all the variables
-7(3x+6)-2
We multiply parentheses
-21x-42-2
We add all the numbers together, and all the variables
-21x-44
Back to the equation:
-(-21x-44)
-2x-(-21x-44)+10=0
We get rid of parentheses
-2x+21x+44+10=0
We add all the numbers together, and all the variables
19x+54=0
We move all terms containing x to the left, all other terms to the right
19x=-54
x=-54/19
x=-2+16/19
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