3x-5(x-4)=-8+4x-2

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Solution for 3x-5(x-4)=-8+4x-2 equation: 



3x-5(x-4)=-8+4x-2

We move all terms to the left:

3x-5(x-4)-(-8+4x-2)=0

We add all the numbers together, and all the variables

3x-5(x-4)-(4x-10)=0

We multiply parentheses

3x-5x-(4x-10)+20=0

We get rid of parentheses

3x-5x-4x+10+20=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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