3x-5(x-4)=-9+3x+19

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Solution for 3x-5(x-4)=-9+3x+19 equation: 



3x-5(x-4)=-9+3x+19

We move all terms to the left:

3x-5(x-4)-(-9+3x+19)=0

We add all the numbers together, and all the variables

3x-5(x-4)-(3x+10)=0

We multiply parentheses

3x-5x-(3x+10)+20=0

We get rid of parentheses

3x-5x-3x-10+20=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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