3x-5(x-4)=2+3+12

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Solution for 3x-5(x-4)=2+3+12 equation: 



3x-5(x-4)=2+3+12

We move all terms to the left:

3x-5(x-4)-(2+3+12)=0

We add all the numbers together, and all the variables

3x-5(x-4)-17=0

We multiply parentheses

3x-5x+20-17=0

We add all the numbers together, and all the variables

-2x+3=0

We move all terms containing x to the left, all other terms to the right

-2x=-3

x=-3/-2

x=1+1/2

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