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3x-5(x-9)x=9
We move all terms to the left:
3x-5(x-9)x-(9)=0
We multiply parentheses
-5x^2+3x+45x-9=0
We add all the numbers together, and all the variables
-5x^2+48x-9=0
a = -5; b = 48; c = -9;
Δ = b2-4ac
Δ = 482-4·(-5)·(-9)
Δ = 2124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2124}=\sqrt{36*59}=\sqrt{36}*\sqrt{59}=6\sqrt{59}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-6\sqrt{59}}{2*-5}=\frac{-48-6\sqrt{59}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+6\sqrt{59}}{2*-5}=\frac{-48+6\sqrt{59}}{-10} $
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