3x-5+2(3x)+13=-3-3x+(3-5)

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Solution for 3x-5+2(3x)+13=-3-3x+(3-5) equation: 



3x-5+2(3x)+13=-3-3x+(3-5)

We move all terms to the left:

3x-5+2(3x)+13-(-3-3x+(3-5))=0

We add all the numbers together, and all the variables

3x+23x-(-3-3x+(-2))-5+13=0

We add all the numbers together, and all the variables

26x-(-3-3x+(-2))+8=0



We calculate terms in parentheses: -(-3-3x+(-2)), so:

-3-3x+(-2)

determiningTheFunctionDomain
-3x-3+(-2)

We add all the numbers together, and all the variables

-3x-5

Back to the equation:

-(-3x-5)



We get rid of parentheses

26x+3x+5+8=0

We add all the numbers together, and all the variables

29x+13=0

We move all terms containing x to the left, all other terms to the right

29x=-13

x=-13/29

x=-13/29

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