3x-5/2=3(3x-1)/5

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Solution for 3x-5/2=3(3x-1)/5 equation: 



3x-5/2=3(3x-1)/5

We move all terms to the left:

3x-5/2-(3(3x-1)/5)=0

We calculate fractions


3x+(-(3(3x-1)*2)/()+()/()=0



We calculate terms in parentheses: +(-(3(3x-1)*2)/()+()/(), so:

-(3(3x-1)*2)/()+()/(

We add all the numbers together, and all the variables

-(3(3x-1)*2)/()+1

We multiply all the terms by the denominator


-(3(3x-1)*2)+1*()



We calculate terms in parentheses: -(3(3x-1)*2), so:

3(3x-1)*2

We multiply parentheses

18x-6

Back to the equation:

-(18x-6)



We add all the numbers together, and all the variables

-(18x-6)

We get rid of parentheses

-18x+6

Back to the equation:

+(-18x+6)



We get rid of parentheses

3x-18x+6=0

We add all the numbers together, and all the variables

-15x+6=0

We move all terms containing x to the left, all other terms to the right

-15x=-6

x=-6/-15

x=2/5

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