3x-5/x+1=x+1

Solution for 3x-5/x+1=x+1 equation:

3x-5/x+1=x+1

We move all terms to the left:

3x-5/x+1-(x+1)=0


Domain of the equation: x!=0

x∈R


We get rid of parentheses

3x-5/x-x-1+1=0

We multiply all the terms by the denominator


3x*x-x*x-1*x+1*x-5=0

We add all the numbers together, and all the variables

3x*x-x*x-5=0

Wy multiply elements

3x^2-1x^2-5=0

We add all the numbers together, and all the variables

2x^2-5=0

a = 2; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·2·(-5)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*2}=\frac{0-2\sqrt{10}}{4}
=-\frac{2\sqrt{10}}{4}
=-\frac{\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*2}=\frac{0+2\sqrt{10}}{4}
=\frac{2\sqrt{10}}{4}
=\frac{\sqrt{10}}{2}
$