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3x-5=(2x+10)
We move all terms to the left:
3x-5-((2x+10))=0
We calculate terms in parentheses: -((2x+10)), so:We get rid of parentheses
(2x+10)
We get rid of parentheses
2x+10
Back to the equation:
-(2x+10)
3x-2x-10-5=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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