3x-5=-10(7+x)

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Solution for 3x-5=-10(7+x) equation: 



3x-5=-10(7+x)

We move all terms to the left:

3x-5-(-10(7+x))=0

We add all the numbers together, and all the variables

3x-(-10(x+7))-5=0



We calculate terms in parentheses: -(-10(x+7)), so:

-10(x+7)

We multiply parentheses

-10x-70

Back to the equation:

-(-10x-70)



We get rid of parentheses

3x+10x+70-5=0

We add all the numbers together, and all the variables

13x+65=0

We move all terms containing x to the left, all other terms to the right

13x=-65

x=-65/13

x=-5

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