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3x-5=11+(x-6)
We move all terms to the left:
3x-5-(11+(x-6))=0
We calculate terms in parentheses: -(11+(x-6)), so:We get rid of parentheses
11+(x-6)
determiningTheFunctionDomain (x-6)+11
We get rid of parentheses
x-6+11
We add all the numbers together, and all the variables
x+5
Back to the equation:
-(x+5)
3x-x-5-5=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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