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3x-5=11+(x/3)
We move all terms to the left:
3x-5-(11+(x/3))=0
We add all the numbers together, and all the variables
3x-(11+(+x/3))-5=0
We multiply all the terms by the denominator
3x*3))-(11+(+x-5*3))=0
We add all the numbers together, and all the variables
3x*3))-(11+(x-15))=0
We add all the numbers together, and all the variables
3x*3))-(11+(x=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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