3x-5=19-(x-2)=-6

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Solution for 3x-5=19-(x-2)=-6 equation: 



3x-5=19-(x-2)=-6

We move all terms to the left:

3x-5-(19-(x-2))=0



We calculate terms in parentheses: -(19-(x-2)), so:

19-(x-2)

determiningTheFunctionDomain
-(x-2)+19

We get rid of parentheses

-x+2+19

We add all the numbers together, and all the variables

-1x+21

Back to the equation:

-(-1x+21)



We get rid of parentheses

3x+1x-21-5=0

We add all the numbers together, and all the variables

4x-26=0

We move all terms containing x to the left, all other terms to the right

4x=26

x=26/4

x=6+1/2

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